Xcode Tabs

Fri, 10 Oct 2014 00:00:00 -0400

I was getting pretty frustrated with Xcode 6 the other day. Specifically, I was getting irritated by constantly having to fiddle with my layout continually getting adjusted.

The Problem

Like many IDEs, Xcode's layout is divided into panes.

Navigator (left side pane)
Editor (center)
Utilities (right side pane)
Debug/Console (bottom pane)

Each of these have quite a few different contextual modes

Navigator Pane

Project Navigator (⌘ 1)
Symbol Navigator (⌘ 2)
Find Navigator (⌘ 3)
Issue Navigator (⌘ 4)
Test Navigator (⌘ 5)
Debug Navigator (⌘ 6)
Breakpoint Navigator (⌘ 7)
Report Navigator (⌘ 8)

Utility Pane

File Inspector (Opt ⌘ 1)
Quick Help Inspector (Opt ⌘ 2)
Identity Inspector (Opt ⌘ 3)
Attributes Inspector (Opt ⌘ 4)
Size Inspector (Opt ⌘ 5)
Connections Inspector (Opt ⌘ 6)

Editor

Standard Editor (⌘ Ret)
Assistant Editor (Opt ⌘ Ret)
Version Editor (Opt Shft ⌘ Ret)

Trello Hash

Wed, 17 Sep 2014 00:00:00 -0400

Our team was looking into project / client management solutions the other day and I came across Trello. While looking around their site, I stumbled upon their developer job listing, which included a challenge to solve as part of the application process. It looked pretty fun, so I tackled it when I got home.

The Challenge

The challenge, in a nutshell, is to reverse engineer a sample hash function. The give pseudocode for the function is as follows:

Int64 hash (String s) {
    Int64 h = 7
    String letters = "acdegilmnoprstuw"
    for(Int32 i = 0; i < s.length; i++) {
        h = (h * 37 + letters.indexOf(s[i]))
    }
    return h
}

The function should work as follows: hash("leepadg") returns 680131659347. The question is, what string returns 956446786872726?

My solution

To really get an understanding of the pseudocode, I decided to implement it in php. Essentially a one-to-one translation is the following:

function hash2($s)
{
    $h = 7;
 
   $letters = "acdegilmnoprstuw";
 
   for ($i=0; $i < strlen($s); $i++) { 
        $pos = strpos($letters, $s[$i]);
        if ($pos === false) {
           $char = $s[$i];
           unset($pos);
           throw new ErrorException("The character {$char} does not exist in the string {$letters}");
       } else {
           $h = ($h * 37 + $pos);
       }
 
 }
   return $h;
}

Reimplementing the function recursively

While going through this, it seemed to me that this would be pretty easy to implement recursively, and I definitely felt that to reverse the hash, I'd have to do it recursively. So, I rewrite the hash function using recursion. To do this, we need to also know how deep to recurse (so that we don't create an infinite recursion loop). So, as a second parameter, we are going to pass strlen($s).

function recursive_hash2($s, $j)
{
    $letters = "acdegilmnoprstuw";
 
   if ($j == 0) {
        return 7;
    } else {
        return recursive_hash2($s, --$j) * 37 + strpos($letters, $s[$j]);
    }
}

Reversing the function

So, in thinking about reversing the hash, I knew that we'd be able to at least get the last letter of the final string (ie, the strpos($letters, $s[$j])) by $number % 37. Then, we could reduce the number by reversing the math with $number - ($number % 37) / 37. I tested this out manually, and verified that it worked, and knew this result is what we would recurse on. But, we'd need to kill recursion at some point, right? That math would just go into negative numbers. So, we'd need a test to kill the recursion. That led me to this final solution:

function reverse_hash2($number)
{
    $letters = "acdegilmnoprstuw";
 
   $reduced = ($number - ($number % 37)) / 37;
    if ($number < 16) {
        return null;
    } else {
        return reverse_hash2($reduced) . $letters[$number%37];
   }   
}

Notice that we need to concatenate the string as the nested functions exit.

I've got the full code available on GitHub. Thanks to Trello for a fun challenge!!